Not necessarily. The sub/super matters because noise is being generated outside of the suppressor, thus reducing its effectiveness.
What actually matters for the "bang" is the pressure of the gas coming out of the barrel, and the size of the barrel. For the same bullet weight and diameter, then sub will always be quieter than super, because there is lower pressure after the bullet leaves. A good way to demonstrate this is with a .22 pistol vs. a .22 rifle. The bullet will always leave the rifle at a higher velocity than the pistol, but the pistol is always louder. Why is that? Because the volume of space in the barrel of the rifle is triple or more that of the pistol, with an accompanying drop in pressure when the bullet leaves the barrel.
Now, I don't know the actual math for caliber vs. pressure and which would contribute more or less. The area of a .45 barrel is larger than a .22, for example, so even though they may be operating at the same pressure (for argument's sake) the .45 generates more noise because there is a bigger volume of gas "shaking" the air around it, which is all that noise is. I would guess that the proper measurement would probably be volume of gas released over a period of time, which would take into account v = nrt/p, and cover all the variables.
H.